给定数字列表, 找到所有可被13整除的数字。
Input : my_list = [12, 65, 54, 39, 102, 339, 221, 50, 70]
Output : [65, 39, 221]我们可以用拉姆达内置filter()函数内部的函数, 以查找列表中所有可被13整除的数字。在Python中, 匿名函数意味着函数没有名称。
Python中的filter()函数接受一个函数和一个列表作为参数。这提供了一种精妙的方法来过滤出序列"序列"的所有元素, 为此函数返回True。
# Python Program to find numbers divisible
# by thirteen from a list using anonymous
# function
# Take a list of numbers.
my_list = [ 12 , 65 , 54 , 39 , 102 , 339 , 221 , 50 , 70 , ]
# use anonymous function to filter and comparing
# if divisible or not
result = list ( filter ( lambda x: (x % 13 = = 0 ), my_list))
# printing the result
print (result)输出如下：
[65, 39, 221]给定一个字符串列表, 找到所有回文。
# Python Program to find palindromes in
# a list of strings.
my_list = [ "geeks" , "geeg" , "keek" , "practice" , "aa" ]
# use anonymous function to filter palindromes.
# Please refer below article for details of reversed
# https://www.lsbin.org/reverse-string-python-5-different-ways/
result = list ( filter ( lambda x: (x = = "".join( reversed (x))), my_list))
# printing the result
print (result)输出：
['geeg', 'keek', 'aa']给定一个字符串列表和一个字符串str, 打印所有str的字谜
# Python Program to find all anagrams of str in
# a list of strings.
from collections import Counter
my_list = [ "geeks" , "geeg" , "keegs" , "practice" , "aa" ]
str = "eegsk"
# use anonymous function to filter anagrams of x.
# Please refer below article for details of reversed
# https://www.lsbin.org/anagram-checking-python-collections-counter/
result = list ( filter ( lambda x: (Counter( str ) = = Counter(x)), my_list))
# printing the result
print (result)输出：
['geeks', 'keegs']注意怪胎！巩固你的基础Python编程基础课程和学习基础知识。
首先, 你的面试准备可通过以下方式增强你的数据结构概念：Python DS课程。
