Python如何从字符串列表中删除空字符串？

在许多情况下, 我们会遇到在大量数据中获取空字符串并处理有时变得乏味的问题。让我们讨论一些从字符串列表中删除空字符串的方法。

方法1：使用remove()

此特定方法非常幼稚, 不建议使用, 但实际上是执行此任务的方法。去掉()通常会删除第一次出现的空字符串, 并且我们会重复进行此过程, 直到在列表中找不到空字符串为止。

# Python3 code to demonstrate 
# removing empty strings 
# using remove()
  
# initializing list 
test_list = [" ", " lsbin ", " ", " is ", " best ", " "]
  
# Printing original list
print ( "Original list is : " + str (test_list))
  
# using remove() to
# perform removal
while ("" in test_list) :
     test_list.remove("")
      
# Printing modified list 
print ( "Modified list is : " + str (test_list))

输出如下：

Original list is : ['', 'lsbin', '', 'is', 'best', '']
Modified list is : ['lsbin', 'is', 'best']

方法2：使用列表理解

更简洁, 更好的方法是删除所有空字符串, 它只是检查字符串是否不为空, 然后使用所有不为空的字符串重新创建列表。

# Python 3 code to demonstrate 
# removing empty strings 
# using list comprehension
  
# initializing list 
test_list = [" ", " lsbin ", " ", " is ", " best ", " "]
  
# Printing original list
print ( "Original list is : " + str (test_list))
  
# using list comprehension to
# perform removal
test_list = [i for i in test_list if i]
      
# Printing modified list 
print ( "Modified list is : " + str (test_list))

输出如下：

Original list is : ['', 'lsbin', '', 'is', 'best', '']
Modified list is : ['lsbin', 'is', 'best']

方法3：使用join() + split()

结合join()和split()操作，也可以实现此任务。我们首先连接所有的字符串以删除空字符串，然后将其分割回列表，这样创建的新列表中就没有空字符串了。

# Python3 code to demonstrate 
# removing empty strings 
# using join() +  split()
  
# initializing list 
test_list = [" ", " lsbin ", " ", " is ", " best ", " "]
  
# Printing original list
print ( "Original list is : " + str (test_list))
  
# using join() +  split() to
# perform removal
test_list = ' ' .join(test_list).split()
      
# Printing modified list 
print ( "Modified list is : " + str (test_list))

输出如下：

Original list is : ['', 'lsbin', '', 'is', 'best', '']
Modified list is : ['lsbin', 'is', 'best']

方法4：使用filter()

使用filter()是执行此任务的最优雅和最快的方法。这种方法是强烈推荐的，因为当我们处理可能包含空字符串的大型机器学习数据集时，速度很重要。

# Python 3 code to demonstrate 
# removing empty strings 
# using filter()
  
# initializing list 
test_list = [" ", " lsbin ", " ", " is ", " best ", " "]
  
# Printing original list
print ( "Original list is : " + str (test_list))
  
# using filter() to
# perform removal
test_list = list ( filter ( None , test_list))
      
# Printing modified list 
print ( "Modified list is : " + str (test_list))

输出如下：

Original list is : ['', 'lsbin', '', 'is', 'best', '']
Modified list is : ['lsbin', 'is', 'best']

首先, 你的面试准备可通过以下方式增强你的数据结构概念：Python DS课程。

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