本文概述
给定一个矩阵, 任务是找到每一列的最大元素。
例子:
Input: [1, 2, 3]
[1, 4, 9]
[76, 34, 21]
Output:
76
34
21
Input: [1, 2, 3, 21]
[12, 1, 65, 9]
[1, 56, 34, 2]
Output:
12
56
65
21
方法:
这个想法是为no_of_cols运行循环。检查列中的每个元素并查找最大元素。最后, 打印元素。
下面是上述方法的实现:
C ++
// C++ program to find the maximum
// element of each column.
#include <bits/stdc++.h>
using namespace std;
const int MAX = 100;
// Function to find the maximum
// element of each column.
void largestInColumn( int mat[][MAX], int rows, int cols)
{
for ( int i = 0; i < cols; i++) {
// initialize the maximum element
// with 0
int maxm = mat[0][i];
// Run the inner loop for rows
for ( int j = 1; j < rows; j++) {
// check if any element is greater
// than the maximum element
// of the column and replace it
if (mat[j][i] > maxm)
maxm = mat[j][i];
}
// print the largest element of the column
cout << maxm << endl;
}
}
// Driver code
int main()
{
int n = 4, m = 4;
int mat[][MAX] = { { 3, 4, 1, 8 }, { 1, 4, 9, 11 }, { 76, 34, 21, 1 }, { 2, 1, 4, 5 } };
largestInColumn(mat, n, m);
return 0;
}
Java
// Java program to find maximum
// element of each column in a matrix
public class GFG {
// Function to find the maximum
// element of each column.
public static void largestInColumn( int cols, int [][] arr)
{
for ( int i = 0 ; i < cols; i++) {
// Initialize max to 0 at beginning
// of finding max element of each column
int maxm = arr[ 0 ][i];
for ( int j = 1 ; j < arr[i].length; j++)
if (arr[j][i] > maxm)
maxm = arr[j][i];
System.out.println(maxm);
}
}
// Driver code
public static void main(String[] args)
{
int [][] arr = new int [][] { { 3 , 4 , 1 , 8 }, { 1 , 4 , 9 , 11 }, { 76 , 34 , 21 , 1 }, { 2 , 1 , 4 , 5 } };
// Calling the function
largestInColumn( 4 , arr);
}
}
Python3
# Python3 program to find the maximum
# element of each column
MAX = 100
# function to find the maximum
# elements of each column
def largestInColumn(mat, rows, cols):
for i in range (cols):
# initialize the maximum element with 0
maxm = mat[ 0 ][i]
# run the inner loop for news
for j in range (rows):
# check if any elements is greater
# than the maximum elements
# of the cloumn and replace it
if mat[j][i] > maxm:
maxm = mat[j][i]
# print the largest element
# of the column
print (maxm)
# Driver code
n, m = 4 , 4
mat = [[ 3 , 4 , 1 , 8 ], [ 1 , 4 , 9 , 11 ], [ 76 , 34 , 21 , 1 ], [ 2 , 1 , 4 , 5 ]]
largestInColumn(mat, n, m);
# This code is contributed
# by Mohit kumar 29 (IIIT gwalior)
C#
// C# program to find maximum
// element of each column in a matrix
using System;
class GFG
{
// Function to find the maximum
// element of each column.
public static void largestInColumn( int cols, int [, ] arr)
{
for ( int i = 0; i < cols; i++)
{
// Initialize max to 0 at beginning
// of finding max element of each column
int maxm = arr[0, i];
for ( int j = 1; j < arr.GetLength(0); j++)
if (arr[j, i] > maxm)
maxm = arr[j, i];
Console.WriteLine(maxm);
}
}
// Driver code
public static void Main()
{
int [, ] arr = new int [, ] { { 3, 4, 1, 8 }, { 1, 4, 9, 11 }, { 76, 34, 21, 1 }, { 2, 1, 4, 5 } };
// Calling the function
largestInColumn(4, arr);
}
}
// This code is contributed
// by Akanksha Rai
的PHP
<?php
// PHP program to find the maximum
// element of each column.
$MAX = 100;
// Function to find the maximum
// element of each column.
function largestInColumn( $mat , $rows , $cols )
{
for ( $i = 0; $i < $cols ; $i ++)
{
// initialize the maximum element
// with 0
$maxm = $mat [0][ $i ];
// Run the inner loop for rows
for ( $j = 1; $j < $rows ; $j ++)
{
// check if any element is greater
// than the maximum element
// of the column and replace it
if ( $mat [ $j ][ $i ] > $maxm )
$maxm = $mat [ $j ][ $i ];
}
// print the largest element
// of the column
echo $maxm , "\n" ;
}
}
// Driver code
$n = 4;
$m = 4;
$mat = array ( array ( 3, 4, 1, 8 ), array ( 1, 4, 9, 11 ), array ( 76, 34, 21, 1 ), array ( 2, 1, 4, 5 ));
largestInColumn( $mat , $n , $m );
// This code is contributed by Sach_Code
?>
输出如下:
76
34
21
11
时间复杂度:O(n * m), 这里n是矩阵的行数, m是矩阵的列数。