Python程序查找列表中的最小数字

2021年3月11日18:13:36 发表评论 854 次浏览

给定一个数字列表, 任务是编写一个Python程序以查找给定列表中的最小数字。

例子:

Input : list1 = [10, 20, 4]
Output : 4

Input : list2 = [20, 10, 20, 1, 100]
Output : 1

方法1:按升序对列表进行排序, 并打印列表中的第一个元素。

# Python program to find smallest 
# number in a list
  
# list of numbers
list1 = [ 10 , 20 , 4 , 45 , 99 ]
  
# sorting the list
list1.sort()
  
# printing the first element
print ( "Smallest element is:" , * list1[: 1 ])

输出如下:

smallest element is: 4

方法2:使用min()方法

# Python program to find smallest 
# number in a list
  
# list of numbers
list1 = [ 10 , 20 , 1 , 45 , 99 ]
  
  
# printing the maximum element
print ( "Smallest element is:" , min (list1))

输出如下:

Smallest element is: 1

方法3:在用户提供的输入中查找最小值列表元素

# Python program to find smallest 
# number in a list
  
# creating empty list
list1 = []
  
# asking number of elements to put in list
num = int ( input ( "Enter number of elements in list: " ))
  
# iterating till num to append elements in list
for i in range ( 1 , num + 1 ):
     ele = int ( input ( "Enter elements: " ))
     list1.append(ele)
      
# print maximum element
print ( "Smallest element is:" , min (list1))

输出如下:

Enter number of elements in list: 4
Enter elements: 12
Enter elements: 19
Enter elements: 11
Enter elements: 99
Smallest element is: 11

方法4:在列表中找到最小的元素。

# Python program to find smallest 
# number in a list
  
l = [l for l in input ( "List:" ).split( ", " )]
print ( "The list is " , l)
  
# Assign first element as a minimum.
min1 = l[ 0 ]
  
for i in range ( len (l)):
  
     # If the other element is min than first element
     if l[i] < min1: 
         min1 = l[i] #It will change
  
print ( "The smallest element in the list is " , min1)

输入如下:

List: 23, -1, 45, 22.6, 78, 100

输出如下:

The list is ['23', '-1', '45', '22.6', '78', '100']
The smallest element in the list is  -1

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